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3/5h^2+7=88
We move all terms to the left:
3/5h^2+7-(88)=0
Domain of the equation: 5h^2!=0We add all the numbers together, and all the variables
h^2!=0/5
h^2!=√0
h!=0
h∈R
3/5h^2-81=0
We multiply all the terms by the denominator
-81*5h^2+3=0
Wy multiply elements
-405h^2+3=0
a = -405; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-405)·3
Δ = 4860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4860}=\sqrt{324*15}=\sqrt{324}*\sqrt{15}=18\sqrt{15}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{15}}{2*-405}=\frac{0-18\sqrt{15}}{-810} =-\frac{18\sqrt{15}}{-810} =-\frac{\sqrt{15}}{-45} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{15}}{2*-405}=\frac{0+18\sqrt{15}}{-810} =\frac{18\sqrt{15}}{-810} =\frac{\sqrt{15}}{-45} $
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